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获取token报404错误

post请求地址https://a1.easemob.com/企业id/应用名称/token
requestbody 中也是按照标准填写,为什么会包404错误,求助啊。
错误信息:
Status Code: 404 Not Found
Access-Control-Allow-Origin: *
Connection: keep-alive
Content-Type: application/json;charset=UTF-8
Date: Thu, 27 Aug 2015 09:21:34 GMT
Server: Tengine/2.0.3
Transfer-Encoding: chunked
responsebody:
{
   "error_description": "invalid username or password",
   "error": "invalid_grant"
}
 
已邀请:
获取token请求体写法格式如下:{"grant_type":"client_credentials",
"client_id":"YXA6pkUGANa6EeSUKBtg-ak7UQ",
"client_secret":"YXA6ZzJ5AzFGPAgYVuYFTtJs_bZnmNI"}   client_id和client_secret不能写成你的用户名和密码,看看你的写法是怎样的? 

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